Sphere Weight Calculator

Sphere Weight Formula:

\[ Weight = \frac{4}{3} \pi r^3 \times Density \]

Weight:

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1. What is the Sphere Weight Calculation?

The sphere weight calculation determines the mass of a spherical object based on its radius and material density. This calculation is essential in physics, engineering, and materials science for determining the weight of spherical objects.

2. How Does the Calculator Work?

The calculator uses the sphere weight formula:

\[ Weight = \frac{4}{3} \pi r^3 \times Density \]

Where:

\( r \) — Radius of the sphere (meters)
\( \pi \) — Mathematical constant pi (approximately 3.14159)
\( Density \) — Material density (kg/m³)

Explanation: The formula first calculates the volume of the sphere using \( \frac{4}{3} \pi r^3 \), then multiplies by the material density to obtain the weight.

3. Importance of Sphere Weight Calculation

Details: Accurate sphere weight calculation is crucial for engineering applications, material selection, structural design, and various scientific calculations involving spherical objects.

4. Using the Calculator

Tips: Enter the radius in meters and density in kg/m³. Both values must be positive numbers. The calculator will compute the weight in kilograms.

5. Frequently Asked Questions (FAQ)

Q1: What units should I use for the inputs?
A: Radius should be in meters (m) and density in kilograms per cubic meter (kg/m³) for the result to be in kilograms.

Q2: Can I use different units?
A: Yes, but you'll need to ensure unit consistency. For example, if you use centimeters for radius, the density should be in kg/cm³.

Q3: What is the typical density range for common materials?
A: Water: 1000 kg/m³, Steel: 7850 kg/m³, Aluminum: 2700 kg/m³, Gold: 19300 kg/m³, Air: 1.225 kg/m³.

Q4: How accurate is this calculation?
A: The calculation is mathematically exact for perfect spheres with uniform density. Real-world accuracy depends on how closely the object approximates a perfect sphere and has uniform density.

Q5: Can this be used for hollow spheres?
A: No, this formula is for solid spheres. For hollow spheres, you would need to calculate the volume of the outer sphere minus the volume of the inner hollow space.